Measurement of Self Inductance of High Quality Factor Coil by Hay's Bridge 
Introduction
Objective
- To determine the self inductance of a high quality factor unknown coil.
- The Hay's bridge is a modification of Maxwell's bridge. The connection diagram is shown in figure 1. This bridge uses a resistance in series with the standard capacitor (unlike the Maxwell bridge which uses a resistance in parallel with capacitor).
Circuit Diagram

Fig 1: Circuit diagram for measurement of self inductance of high quality factor coil by Hay's bridge
Let,
L1= Unknown inductance having resistance R1.
R2, R3, R4= known non inductive resistance.
C4 = Standard capacitor.
At Balance,
$$ (R_1 + j * \omega * L_1) * (R_4 - \frac{j}{\omega * C_4 }) = R_2 * R_3 $$
$$ R_1 * R_4 + \frac{L_1}{C_4} + j * \omega * L_1 * R_4 - j * \frac{R_1}{(\omega * C_4) }= R_2 * R_3 $$
separating the real and imaginary terms, we get
$$ R_1R_4 + \frac{L_1}{C_4} = R_2R_3 . . . . . . . . . (1) $$
$$ j * \omega * L_1R_4 - \frac{jR_1}{\omega C_4 } = 0 . . . . . . (2) $$
Solving the above two equations(1) and (2), we have,
$$ L_1 =\frac{R_2R_3C_4}{1 + \omega^2 C_4^2 R_4^2} $$
$$ R_1 = \frac{\omega^2C_4^2R_4R_2R_3}{1 + \omega^2C_4^2R_4^2} $$
The Quality factor of the coil
$$ Q = \frac{\omega L_1}{R_1} = \frac{1}{\omega C_4R_4} $$