1. Keep all the resistance close to their maximum respective values.
2. Close the switch s₁ to "aa" and s₂ to "cc" positions. Observes the load current I_L and voltage V_L readings. The load resistance,
   R_L = V_L / I_L
3. Short the load terminals and find the short circuited current I_sc.
4. Next, compute the resistance R_int of the network as seen from the load terminals,
   • Replace the 220 V source by a short by closing s₁ to "bb".
   • Apply V=110 V at the output terminals by closing s₂ to "dd". Read the current from ammeter (I) and get R_int = V/I
5. Now compute the load current I_L applying Norton theorem.
$$I_L=I_{sc}\frac{R_{int}}{(R_{int}+R_L)}$$
6. Compare the above computed load current with its observed value in step (2) and verify the theorem.