Virtual Labs

If I=33∠-13º , find the Thevenin’s equivalent circuit to the left of terminal x-y in the network of Fig in below.

a: 4.545∠58º Ω, 150∠45º V Explanation

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b: 4.545∠48º Ω, 15∠45º V Explanation

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c: 4.75∠58º Ω, 75∠45º V Explanation

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d: 9.545∠58º Ω, 150∠45º V Explanation

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Find the current in 10 Ω resistor using Thevnin’s Theorem .

a: 9.35∠28.3º A Explanation

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b: 9.35∠58.3º A Explanation

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c: 7.35∠28.3º A Explanation

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d: 7.35∠58.3º A Explanation

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Find Thevenin’s equivalent circuit of the network.

a: V_o.c=(6.5 - sin wt ) V and R_th= 20Ω Explanation

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b: V_o.c=(6.5 - sin wt ) V and R_th= 10Ω Explanation

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c: V_o.c=(8.5 - sin wt ) V and R_th= 15Ω Explanation

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d: V_o.c=(6.5 - cos wt ) V and R_th= 15Ω Explanation

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Find the Thevenin’s equivalent network. The voltage source 10∠30º has internal resistance of 1Ω.

a: V_o.c=(-18.68-j3.22)V; Z_int=2.08∠-180ºΩ Explanation

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b: V_o.c=(-12.37-j7.14)V; Z_int=2.08∠-180ºΩ Explanation

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c: V_o.c=(-12.37-j7.14)V; Z_int=1.43∠-180ºΩ Explanation

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d: V_o.c=(-18.68-j3.22)V; Z_int=1.43∠-180ºΩ Explanation

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In the network find the current through the 10Ω resistor utilizing Thevenin’s Theorem.

a: 1.44A Explanation

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b: 3.75A Explanation

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c: 8.3A Explanation

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d: 1.26A Explanation

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Determine the current through the 5Ω resistor in the circuit.

a: 1A Explanation

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b: 2A Explanation

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c: 4A Explanation

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d: 5A Explanation

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What is the current in the 10Ω resistor? Use Thevenin’s Theorem.

a: 0.625A Explanation

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b: 2.5A Explanation

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c: 0.315A Explanation

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d: 1.25A Explanation

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Verification of Thevenin Theorem